Physics Questions Regarding Application of Newton's Second Law?
A toy rocket of mass 50 grams can accelerate horizontally with an acceleration of 29.8 m/sec2. The rocket engine operates for 3 seconds before burnout...
A toy rocket of mass 50 grams can accelerate horizontally with an acceleration of 29.8 m/sec2. The rocket engine operates for 3 seconds before burnout, and provides constant thrust (force) during its burn. Assuming negligible air friction, how high will it go when fired straight up?
Mother of 6 kids pulls two carts of groceries connected by a rope through the grocery store. The first cart is full and has a mass of 60.2 kg and the second cart is full of potato chips and weighs 125 Newtons. She is late for piano lessons so she runs through the store exerting a force of 90 Newtons on the carts. What is the tension in the rope?
At lift off, the three main engines and the two booster rockets of the 4.5X106 lb space shuttle produced 6.4X106 lbs of thrust vertically downward. What was the acceleration at liftoff and assuming the acceleration remains constant how long did it take the shuttle to rise through its own height of 184 ft?
Questions are just for fun, not graded, just curious to see what you get
Please give me numbers, as well as procedure. Answer what you can.
Related posts:
Hello
The vertical acceleration is 29,8 m/s^2, the vertical acceleration is 20 m/s^2.
v= a*t = 20*3 = 60 m/s
s = v*t–> the average v = 30 m/s, s = 30*3 = 90 m after the first 3 seconds. The further height reached is h = v0^2/2g = 183,4 m and
total height = 183,4+90 = 273,4 m.
The first cart has a ass of 60,2 kg, the second a mass of 12,74 kg
When she pulls with 90 N the acceleration is a = F/m = 90 N/72,9 kg = 1,23 m/s^2.
The tension in the rope between the carts:
tension = F = ma = 12,74 kg*1,23 m/s^2 = 15,67 N
The weight of the shuttle: 2,038*10^6 kg*9,81 = 20*10^6 N
The thrust = 2,8*10^6 kg = 27,46*10^6 N
Net force =Differenz = 7,48*10^6 N
a = F/m = 7,48*10^6 N/2,038*10^6 kg = 3,68 m/s^2
s = 1/2 at^2
t = √(2s/a) = √2*56,08m/3,68m/s^2)
t = 5,5 seconds
Regards